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Natrium EDTA frei 500g Acerola Chemische Form: C₄H₈O₂

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Chemische Form: C₄H₈O₂

0 Äußeres Erscheinungsbild weißes oder fast weißes Pulver

Aussehen: rötlich-brauner Feststoff

Chemische Formel: K₂Cr₂O₇

Industrielle Fertigung: Lösemittel in Lacken

Natrium EDTA frei 500g Acerola Chemische Form: C₄H₈O₂

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